x^2+x(x+3)=20

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Solution for x^2+x(x+3)=20 equation:


Simplifying
x2 + x(x + 3) = 20

Reorder the terms:
x2 + x(3 + x) = 20
x2 + (3 * x + x * x) = 20
x2 + (3x + x2) = 20

Reorder the terms:
3x + x2 + x2 = 20

Combine like terms: x2 + x2 = 2x2
3x + 2x2 = 20

Solving
3x + 2x2 = 20

Solving for variable 'x'.

Reorder the terms:
-20 + 3x + 2x2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + 3x + 2x2 = 0

Factor a trinomial.
(-4 + -1x)(5 + -2x) = 0

Subproblem 1

Set the factor '(-4 + -1x)' equal to zero and attempt to solve: Simplifying -4 + -1x = 0 Solving -4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1x = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1x = 0 + 4 -1x = 0 + 4 Combine like terms: 0 + 4 = 4 -1x = 4 Divide each side by '-1'. x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(5 + -2x)' equal to zero and attempt to solve: Simplifying 5 + -2x = 0 Solving 5 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2x = 0 + -5 -2x = 0 + -5 Combine like terms: 0 + -5 = -5 -2x = -5 Divide each side by '-2'. x = 2.5 Simplifying x = 2.5

Solution

x = {-4, 2.5}

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